C++ logarithmic function log() operation

First of all, we must know the exp() function

exp(n) value is e^n power;

In addition, the log function includes two functions, a log() function with e as low

The other is the log 10() function with base 10 as the base;

For specific usage, see this small program below

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	double a=9,b=10;
	cout<<log(a)<<endl;
	cout<<log(exp(a))<<endl;
	cout<<log10(b)<<endl;
	return 0;
}

In addition, if you customize to base m, find the value of log n

Need double a=log(n)/log(m);

Examples are as follows:

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	double a=2,b=2;//Logarithmic function with base 2 
	for(b=2;b<=16;b=b+2)
	{
	        When cout<<"b="<<b<<", the base 2 logarithmic function="<<log(b)/log(a)<<endl;
	}
	return 0;
}

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