Click the person data submitted by the submit button loop to the submission API separately
Since the submission method is Ajax is asynchronous, the simple loop submission will appear in order
So use async AWAIT to block
onSubmit() {
let that =this
Let asynclist = [] // Ajax method array
for(let i=0;i<that.selectEmployees.length;i++) {
Let Arg = That.SelectemPloyees [i] // Need to pass the parameters
async function test(arg){enroll(arg.employeeId, that.courseId, 'UNCANCELED')}
Asynclist.push ({func: test, argument: arg}) // Put the test method in an array, by the way
};
async function async(){
For (var i = 0; i <askNCLIST.LENGTH; i ++) {// cycle AJAX method array
AWAIT AsyncList [i] .func (asynclist [i] .Argument) .Then (() => {//. THEN can further process the return value
Console.log ('has executed' + i)
})
}
}
Async (). Then (() => {// All Ajax execution processing
Console.log ('execution is ")
})
},
The above code can actually simplify
function fuc1(){
return new Promise((resolve)=>{
setTimeout(() => {
resolve('fuc1')
console.log('fuc1')
}, 2000);
})
};
function fuc2(){
return new Promise((resolve)=>{
setTimeout(() => {
resolve('fuc2')
console.log('fuc2')
}, 1000);
})
};
var list=[fuc1,fuc2]
async function fuc(){
for(var i=0;i<list.length;i++){
console.log(list[i])
await list[i]().then(console.log(i+'done'))
}
};
fuc().then(()=>{console.log('all done')})
AWAIT will block the current async
The problem with the execution order can be referred to, quite quite detailed
https://blog.csdn.net/m0_37922914/article/details/108564884
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