JAVA Processing JSONOBJECT JSONARRAY

In the process of learning Java, we will inevitably encounter to process JSON data formats, and now you will introduce JSON in Java.
1, handle JSONOBJECT

public static void main(String[] args) {
         String student="{\"name\":\"lixinxin\",\"age\":\"18\",\"price\":\"29\"}";
        JSONObject json = (JSONObject) JSONObject.parse(student);
         // Know KEY, you can directly remove the data directly.
           System.out.println(json.get("name"));
           // I don't know if we can traverse data through iterators.
        Iterator iterator=json.keySet().iterator();
        while (iterator.hasNext()) {
            // Traverse the key to remove the data in Key
            String inputkey = (String)iterator.next();
              System.out.println(inputkey+"=="+json.get(inputkey));
        }
    }

2, handle JSonarray

public static void main(String[] args) {
         String student="[{\"name\":\"lixinxin\",\"age\":\"18\",\"price\":\"29\"},{\"name\":\"zhangsan\",\"age\":\"89\",\"price\":\"299\"}]";
        JSONArray jsonArray= JSON.parseArray(student);
        // for loop traversal object
        for (Object object:jsonArray) {
            // Remove the first data
            System.out.println(object.toString());
            / / Remove the JSonarray to JSONOBJEC
            JSONObject json = (JSONObject) JSONObject.parse(object.toString());
            // This can be taken directly.
            System.out.println(json.get("name"));
        }

    }

Simple and easy to understand is my pursuit

Intelligent Recommendation

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